无法匹配后续的regex模式
我需要从主字符串中提取以下字符串：
roundcube_sessauth=-del-; expires=Thu, 06-Aug-2015 03:38:33 GMT; path=/; secure; httponly，
roundcube_sessid=dh7a60r14c6qfa3lr7m90; path=/; secure; HttpOnly，
roundcube_sessauth=S2124929b7486e6805d615a86; path=/; secure; httponly
主要字符串是：
roundcube_sessauth=-del-; expires=Thu, 06-Aug-2015 03:38:33 GMT; path=/; secure; httponly, roundcube_sessid=dh7a60r14c6qfa3lr7m90; path=/; secure; HttpOnly, roundcube_sessauth=S2124929b7486e6805d615a86; path=/; secure; httponly
我的正则表达式是(roundcube.*?httponly){1}，它与第一个字符串完全匹配。然而，它不匹配第二次或第三次出现，即(roundcube.*?httponly){2}和(roundcube.*?httponly){3}
请告诉我我做错了什么。我试着用PHP来做这件事。
回答 2
Stack Overflow用户
发布于 2015-08-06 07:07:10
您只使用限制量词{1}显式地告诉regex引擎匹配1。把它移开，正则表达式就会起作用。
另外，我建议用字界来使它更安全：
\broundcube.*?\bhttponly\b请参阅演示 (使用不光彩的选项！)
在PHP中，只有拿火柴，而不是组。
$re = '/\broundcube.*?\bhttponly\b/i';
$str = "roundcube_sessauth=-del-; expires=Thu, 06-Aug-2015 03:38:33 GMT; path=/; secure; httponly, roundcube_sessid=dh7a60r14c6qfa3lr7m90; path=/; secure; HttpOnly, roundcube_sessauth=S2124929b7486e6805d615a86; path=/; secure; httponly";
preg_match_all($re, $str, $matches);
print_r($matches[0]);如果输入中有换行符，则添加/s修饰符，以便.也可以匹配换行符。
Stack Overflow用户
发布于 2015-08-06 07:07:31
(roundcube[\s\S]*?httponly)您需要使.匹配newlines或使用[\s\S] instead.Use i标志too.See演示。
https://regex101.com/r/fM9lY3/22
$re = "/(roundcube[\\s\\S]*?httponly)/mi";
$str = "roundcube_sessauth=-del-; expires=Thu, 06-Aug-2015 03:38:33 GMT; path=/; secure; httponly, roundcube_sessid=dh7a60r14c6qfa3lr7m90; path=/; secure; HttpOnly, roundcube_sessauth=S2124929b7486e6805d615a86; path=/; secure; httponly";
preg_match_all($re, $str, $matches);https://stackoverflow.com/questions/31848906
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