问按数字顺序+字母重命名文件

EN

from itertools import product
import os

os.chdir(directory_containing_images)
# instead of hard-coding files you will actually want:
# files = os.listdir('.')
files = ['image1.png', 'image2.png', 'image3.png', 'image4.png', 'image5.png', 'image6.png']
for file, (n, a) in zip(files, product(range(1, len(files) // 3 + 2), 'abc')):
    os.rename(file, '{}-{}.png'.format(n, a))

image1.png 1-a.png
image2.png 1-b.png
image3.png 1-c.png
image4.png 2-a.png
image5.png 2-b.png
image6.png 2-c.png

my @new_names = map {
    my ( $n ) = $_ =~ /image(\d+)\.png/;
    my $j = (($n - 1)  % 3) + 1;
    my $char = (qw(a b c))[ int( $n / 3 ) ];
    "$j-$char.png"
} @files;

declare -i ctr=1 fileset=1              # tracking numbers
declare -a tag=( c a b )                # lookup table
for f in $( printf "%s\n" *.png |       # stack as lines
            sort -k1.6n )               # order appropriately
do ref=$(( ctr++ % 3 ))                 # index the lookup
   end=${f##*.}                         # keep the file ending
   mv "$f" "$fileset-${tag[ref]}.$end"  # mv old file to new name
   (( ref )) || (( fileset++ ))         # increment the *set*
done

mv image1.png 1-a.png
mv image2.png 1-b.png
mv image3.png 1-c.png
mv image4.png 2-a.png
mv image5.png 2-b.png
mv image6.png 2-c.png
mv image7.png 3-a.png
mv image8.png 3-b.png
mv image9.png 3-c.png
mv image10.png 4-a.png
mv image11.png 4-b.png
mv image12.png 4-c.png