我有下面的字典,它代表了一个人,可能是许多变体中的一个。这里只有几个:
person = {"name": "Johnny"}
person = {"name": "Johnny", "age": 25}
person = {"name": "Johnny", "age": 25, "active": True}我正在提取某些键,并使用它们来打印一条语句。问题出现在类型提示中,当我在脚本上运行mypy时,我得到了一个错误Incompatible types in assignment (expression has type "object", variable has type "Optional[str]"):
name: Optional[str] = person.get("name") # mypy error here
age: Optional[int] = person.get("age") # mypy error here
if name and age:
print(f"In 5 years, {name} will be {age + 5} years old")为了解决这个问题,mypy_extensions.TypedDict类型似乎很有希望,但似乎我不能有丢失或额外的键:
from mypy_extensions import TypedDict
PersonDict = TypedDict("PersonDict", {"name": str, "age": int})
# ERROR: Key 'age' missing for TypedDict "PersonDict"
person: PersonDict = {"name": "Johnny"}
# ERROR: Extra key 'active' for TypedDict "PersonDict"
person: PersonDict = {"name": "Johnny", "age": 25, "active": True}有没有办法为字典中的特定键定义类型,即使字典中的键是动态的?
发布于 2019-06-29 09:12:54
将total=False添加到您的TypedDict将允许缺少密钥:
PersonDict = TypedDict("PersonDict", {"name": str, "age": int}, total=False)https://mypy.readthedocs.io/en/latest/more_types.html#totality
允许不在架构中的其他键似乎是不可能的。
https://stackoverflow.com/questions/56677431
复制相似问题