好的,我有一个函数,它接受JSONB类型,并根据该数据块中的各种键执行SELECT和INSERT。PostgreSQL抛出了关于PERFORM和INSERT的错误。在SQL查询中,json数据的正确用法是什么?
CREATE OR REPLACE FUNCTION add_revision(d jsonb)
RETURNS jsonb AS $$
DECLARE
did INT;
BEGIN
did:=get_drawing_id(d->>'Name');
IF did=NULL THEN
did:=create_drawing(d->>'Name',d->>'Discipline',
d->>'Doc Type');
END IF;
PERFORM * FROM revisions WHERE drawingid=did AND Sequence=d->>'Sequence';
IF NOT FOUND THEN
INSERT INTO revisions (Sequence,Revision,State,Meta) VALUES(d->>'Sequence',
d->>'Version',d->>'State',d);
RETURN jsonb_build_object('ok',true);
END IF;
RETURN jsonb_build_object('ok',false,'message','Already exists');
END;
$$ LANGUAGE plpgsql;下面是抛出的错误
Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42883]: Un
defined function: 7 ERROR: operator does not exist: integer = text
LINE 1: ... * FROM revisions WHERE drawingid=did AND Sequence=(d->>'Seq...发布于 2019-02-13 18:25:55
不能将整数与文本进行比较。PostgreSQL是严格的。
检查此部分中的类型。
drawingid=did AND Sequence=d->>'Sequence'这应该不是与JSONB相关的问题。
发布于 2019-02-13 19:04:34
在查询中使用JSONB函数是非常好的,我只需要将类型转换为所需的类型:
CREATE OR REPLACE FUNCTION add_drawing_revision(d jsonb)
RETURNS jsonb AS $$
DECLARE
did INT;
BEGIN
did:=get_drawing_id(d->>'Name');
IF did<0 THEN
did:=create_drawing(d->>'Name',d->>'Discipline',
d->>'Doc Type');
END IF;
PERFORM * FROM revisions WHERE drawingid=did AND Sequence=(d->>'Sequence')::INT;
IF NOT FOUND THEN
INSERT INTO revisions (Sequence,Revision,State,Meta) VALUES((d->>'Sequence')::INT,
d->>'Version',d->>'State',d);
RETURN jsonb_build_object('ok',true);
END IF;
RETURN jsonb_build_object('ok',false,'message','Already exists');
END;
$$ LANGUAGE plpgsql;https://stackoverflow.com/questions/54667530
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