问从最大值开始获取列表的第n个元素

EN

newy = y[idx%reprate::reprate]

import random
# Generating the random list
y = random.sample(range(1, 1000), 1000)
n = 3

# This will get the index of the max element
index = max(enumerate(y), key=lambda x: x[1])[0]

# This will get every `n` element
every_n_element = [y[(i + index) % len(y)] for i in range(0, len(y), n)]
print(every_n_element)

>>> a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>> a[4::2]
[5, 7, 9]
>>> a[4::-2]
[5, 3, 1]