在Swift 3中将JSON数据转换为可用的变量

import Foundation

// 定义一个包含JSON数据的字符串
let jsonString = """
{
    "name": "John Doe",
    "age": 30,
    "email": "johndoe@example.com"
}
"""

// 将JSON字符串转换为Data类型
guard let jsonData = jsonString.data(using: .utf8) else {
    print("Invalid JSON string")
    return
}

do {
    // 将Data类型的JSON数据解析为可用的变量
    guard let json = try JSONSerialization.jsonObject(with: jsonData, options: []) as? [String: Any] else {
        print("Failed to parse JSON data")
        return
    }
    
    // 从解析后的JSON数据中获取特定的值
    if let name = json["name"] as? String {
        print("Name: \(name)")
    }
    
    if let age = json["age"] as? Int {
        print("Age: \(age)")
    }
    
    if let email = json["email"] as? String {
        print("Email: \(email)")
    }
} catch {
    print("Error: \(error)")
}