如何在基于USB物理端口的pyaudio中打开特定设备？

import pyaudio

p = pyaudio.PyAudio()
device_count = p.get_device_count()
for i in range(device_count):
    device_info = p.get_device_info_by_index(i)
    print(f"Device {i}: {device_info['name']}")

device_index = 0  # 设备索引号
device_name = "USB Audio Device"  # 设备名称
for i in range(device_count):
    device_info = p.get_device_info_by_index(i)
    if device_info["name"] == device_name:
        device_index = i
        break

stream = p.open(
    format=pyaudio.paInt16,
    channels=1,
    rate=44100,
    input=True,
    input_device_index=device_index,
    frames_per_buffer=1024
)