如何在GetFiles中获取多关键字文件数

import os

def get_files_with_keywords(directory, keywords):
    file_count = 0

    for root, dirs, files in os.walk(directory):
        for file in files:
            file_path = os.path.join(root, file)
            with open(file_path, 'r') as f:
                content = f.read()
                if all(keyword in content for keyword in keywords):
                    file_count += 1

    return file_count

# 示例用法
directory_path = '/path/to/directory'
search_keywords = ['keyword1', 'keyword2', 'keyword3']
result = get_files_with_keywords(directory_path, search_keywords)
print(f"Number of files containing all keywords: {result}")