如何将文件名作为参数传递，创建并读取文件

    file_name = "example.txt"
    file = open(file_name, "w")
    # 文件操作...
    file.close()

    file_name = "example.txt"
    file = open(file_name, "r")
    content = file.read()
    # 处理文件内容...
    file.close()

    String fileName = "example.txt";
    File file = new File(fileName);
    // 文件操作...

    String fileName = "example.txt";
    File file = new File(fileName);
    BufferedReader reader = new BufferedReader(new FileReader(file));
    String line;
    while ((line = reader.readLine()) != null) {
        // 处理文件内容...
    }
    reader.close();

    const fs = require('fs');
    const fileName = "example.txt";
    fs.writeFileSync(fileName, "Hello, world!");
    // 文件操作...

    const fs = require('fs');
    const fileName = "example.txt";
    const content = fs.readFileSync(fileName, 'utf-8');
    // 处理文件内容...