如何检测两个bufferGeometryBox的两个面的交点？

// 创建两个 BufferGeometry
const geometry1 = new THREE.BufferGeometry();
const geometry2 = new THREE.BufferGeometry();

// 获取顶点数据
const positions1 = geometry1.getAttribute('position').array;
const positions2 = geometry2.getAttribute('position').array;

// 获取索引数据
const indices1 = geometry1.getIndex().array;
const indices2 = geometry2.getIndex().array;

// 创建 Raycaster 对象
const raycaster = new THREE.Raycaster();

// 存储交点信息的数组
const intersections = [];

// 遍历第一个 BufferGeometry 的面
for (let i = 0; i < indices1.length; i += 3) {
  const face1 = [
    new THREE.Vector3(positions1[indices1[i] * 3], positions1[indices1[i] * 3 + 1], positions1[indices1[i] * 3 + 2]),
    new THREE.Vector3(positions1[indices1[i + 1] * 3], positions1[indices1[i + 1] * 3 + 1], positions1[indices1[i + 1] * 3 + 2]),
    new THREE.Vector3(positions1[indices1[i + 2] * 3], positions1[indices1[i + 2] * 3 + 1], positions1[indices1[i + 2] * 3 + 2])
  ];

  // 遍历第二个 BufferGeometry 的面
  for (let j = 0; j < indices2.length; j += 3) {
    const face2 = [
      new THREE.Vector3(positions2[indices2[j] * 3], positions2[indices2[j] * 3 + 1], positions2[indices2[j] * 3 + 2]),
      new THREE.Vector3(positions2[indices2[j + 1] * 3], positions2[indices2[j + 1] * 3 + 1], positions2[indices2[j + 1] * 3 + 2]),
      new THREE.Vector3(positions2[indices2[j + 2] * 3], positions2[indices2[j + 2] * 3 + 1], positions2[indices2[j + 2] * 3 + 2])
    ];

    // 设置射线的起点和方向
    raycaster.set(face1[0], face1[1].sub(face1[0]).cross(face1[2].sub(face1[0])).normalize());

    // 检测射线与三角形的相交情况
    const result = raycaster.intersectTriangle(face2[0], face2[1], face2[2]);

    // 如果有交点，则记录交点信息
    if (result !== null) {
      intersections.push({
        point: result.point,
        distance: result.distance
      });
    }
  }
}

// 打印交点信息
console.log(intersections);