如何比较两个数组，并在typescript中从大到短添加缺少的元素？

const arrayA = [1, 2, 3, 4, 5];
const arrayB = [3, 4, 5, 6, 7];
const missingElements = arrayB.filter(element => !arrayA.includes(element));
console.log(missingElements); // 输出 [6, 7]

missingElements.sort((a, b) => b - a);
console.log(missingElements); // 输出 [7, 6]

missingElements.forEach(element => arrayA.push(element));
console.log(arrayA); // 输出 [1, 2, 3, 4, 5, 7, 6]