如何阻止Apify保存已处理的请求？

const { Apify } = require('apify');

Apify.main(async () => {
    // 创建一个RequestList对象，包含所有要处理的URL
    const requestList = new Apify.RequestList({
        sources: [
            { url: 'http://example.com/page1' },
            { url: 'http://example.com/page2' },
        ],
    });
    await requestList.initialize();

    const crawler = new Apify.CheerioCrawler({
        requestList,
        // 设置请求拦截器，检查并阻止保存已处理的请求
        requestInterceptors: [(request) => {
            if (request.url.includes('processed')) {
                throw new Error('Already processed');
            }
            return request;
        }],
        handlePageFunction: async ({ request, $ }) => {
            // 处理页面的逻辑
            console.log(`Processing page ${request.url}`);
        },
    });

    await crawler.run();
});

const { Apify } = require('apify');

Apify.main(async () => {
    // 创建一个RequestList对象，包含所有要处理的URL
    const requestList = new Apify.RequestList({
        sources: [
            { url: 'http://example.com/page1' },
            { url: 'http://example.com/page2' },
        ],
    });
    await requestList.initialize();

    const crawler = new Apify.CheerioCrawler({
        requestList,
        // 自定义请求处理函数，在其中判断是否保存已处理的请求
        handleRequestFunction: async ({ request }) => {
            if (request.url.includes('processed')) {
                return new Apify.Response({ body: '', contentType: 'text/html' });
            }
        },
        handlePageFunction: async ({ request, $ }) => {
            // 处理页面的逻辑
            console.log(`Processing page ${request.url}`);
        },
    });

    await crawler.run();
});