循环遍历元组列表时的迭代问题

# 定义一个包含元组的列表
people = [("Alice", 30), ("Bob", 25), ("Charlie", 35)]

# 使用for循环遍历列表中的每个元组
for person in people:
    name, age = person  # 解包元组
    print(f"Name: {name}, Age: {age}")

Name: Alice, Age: 30
Name: Bob, Age: 25
Name: Charlie, Age: 35

people = [("Alice", 30), ("Bob", 25, "Engineer"), ("Charlie", 35)]

for person in people:
    name, age = person  # 这里会引发 ValueError
    print(f"Name: {name}, Age: {age}")

for person in people:
    if len(person) == 2:
        name, age = person
        print(f"Name: {name}, Age: {age}")
    else:
        name, age, job = person
        print(f"Name: {name}, Age: {age}, Job: {job}")

people = [("Alice", 30), ("Bob", 25), ("Charlie", 35)]

for person in people:
    if person[0] == "Bob":
        people.remove(person)  # 这里可能会跳过某些元素

people = [("Alice", 30), ("Bob", 25), ("Charlie", 35)]
new_people = []

for person in people:
    if person[0] != "Bob":
        new_people.append(person)

people = new_people