替换嵌套字典python中的NaN值

def replace_nan(dictionary):
    for key, value in dictionary.items():
        if isinstance(value, dict):
            replace_nan(value)  # 递归调用处理嵌套字典
        elif isinstance(value, float) and math.isnan(value):
            dictionary[key] = None  # 将NaN值替换为None或其他你想要的值

# 示例字典
nested_dict = {
    'key1': {
        'subkey1': 1.0,
        'subkey2': float('nan'),
        'subkey3': {
            'subsubkey1': float('nan'),
            'subsubkey2': 2.0
        }
    },
    'key2': float('nan')
}

replace_nan(nested_dict)
print(nested_dict)

{
    'key1': {
        'subkey1': 1.0,
        'subkey2': None,
        'subkey3': {
            'subsubkey1': None,
            'subsubkey2': 2.0
        }
    },
    'key2': None
}