矩阵中至少有1个负值的列的总数

def count_negative_columns(matrix):
    count = 0
    for col in range(len(matrix[0])):
        for row in range(len(matrix)):
            if matrix[row][col] < 0:
                count += 1
                break
    return count

# 示例矩阵
matrix = [
    [1, 2, -3, 4],
    [-5, 6, 7, 8],
    [9, 10, 11, 12]
]

# 调用函数计算矩阵中至少有1个负值的列的总数
result = count_negative_columns(matrix)
print("矩阵中至少有1个负值的列的总数为:", result)

矩阵中至少有1个负值的列的总数为: 2