Python以递归方式合并深度嵌套的字典，并为键重叠的值创建一个列表

def merge_dicts(dict1, dict2):
    for key in dict2:
        if key in dict1:
            if isinstance(dict1[key], dict) and isinstance(dict2[key], dict):
                merge_dicts(dict1[key], dict2[key])
            else:
                if not isinstance(dict1[key], list):
                    dict1[key] = [dict1[key]]
                if not isinstance(dict2[key], list):
                    dict2[key] = [dict2[key]]
                dict1[key].extend(dict2[key])
        else:
            dict1[key] = dict2[key]
    return dict1

# 示例
dict1 = {'a': 1, 'b': {'c': 2, 'd': 3}}
dict2 = {'b': {'c': 4, 'e': 5}, 'f': 6}

merged_dict = merge_dicts(dict1, dict2)
print(merged_dict)

{'a': 1, 'b': {'c': [2, 4], 'd': 3, 'e': 5}, 'f': 6}