array.concat()的问题

let newArray = array1.concat(array2, array3, ..., value1, value2, ...);

let arr1 = [1, 2, 3];
let arr2 = [4, 5, 6];
let arr3 = [7, 8, 9];

let combinedArray = arr1.concat(arr2, arr3, 10, 11);

console.log(combinedArray); // 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
console.log(arr1); // 输出: [1, 2, 3] (原数组未改变)
console.log(arr2); // 输出: [4, 5, 6] (原数组未改变)
console.log(arr3); // 输出: [7, 8, 9] (原数组未改变)

let combinedArray = [...arr1, ...arr2, ...arr3, 10, 11];

let combinedArray = arr1.slice(); // 创建 arr1 的副本
Array.prototype.push.apply(combinedArray, arr2);
Array.prototype.push.apply(combinedArray, arr3);
combinedArray.push(10, 11);