jQuery:如何处理sortable('serialize')返回的列表？

<ul id="sortable">
  <li class="ui-state-default">Item 1</li>
  <li class="ui-state-default">Item 2</li>
  <li class="ui-state-default">Item 3</li>
  <li class="ui-state-default">Item 4</li>
  <li class="ui-state-default">Item 5</li>
</ul>

$( "#sortable" ).sortable();

$( "#submit" ).click(function() {
  var sortedList = $( "#sortable" ).sortable( "serialize" );
  console.log(sortedList);
});

var decodedSortedList = decodeURIComponent(sortedList);
var sortedArray = decodedSortedList.split('&');

$.ajax({
  url: "your_server_url",
  type: "POST",
  data: { sortedList: sortedArray },
  success: function(response) {
    console.log(response);
  },
  error: function(error) {
    console.log(error);
  }
});