【PAT甲级】 A+B Format

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Problem Description：

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −10​6​​≤a,b≤10​6​​. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

解题思路：

人生苦短，我用（xiang）Py。我用C++写的一个只有14分。。。。

AC代码：

a,b = map(int,input().split())
print(format(a+b,','))

C++14分代码：

#include <bits/stdc++.h>
using namespace std;

int main()
{
	int a,b;
	cin >> a >> b;
	int sum = a + b;
	string str = to_string(sum);
    stack<char> s;   //利用栈“先进后出”这个性质
    //将字符串中的字符全部推入栈中
    for(auto it : str)
    {
        s.push(it);
    }
    string result = "";
    int cnt = 0;
    while(!s.empty())   //清仓大甩卖
    {
        cnt++;
        result = s.top() + result;
        s.pop();
        if(cnt == 3)   //每三位数加一个逗号
        {
            result = "," + result;
        }
    }
    cout << result << endl;
    return 0;
}