题目介绍: 文章浏览 II article-views-ii
SQL架构
Table:
Views
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| article_id | int |
| author_id | int |
| viewer_id | int |
| view_date | date |
+---------------+---------+
此表无主键,因此可能会存在重复行。此表的每一行都表示某人在某天浏览了某位作者的某篇文章。 请注意,同一人的 author_id 和 viewer_id 是相同的。
编写一条 SQL 查询来找出在同一天阅读至少两篇文章的人,结果按照 id 升序排序。
查询结果的格式如下:
``` Views table: +------------+-----------+-----------+------------+ | article_id | author_id | viewer_id | view_date | +------------+-----------+-----------+------------+ | 1 | 3 | 5 | 2019-08-01 | | 3 | 4 | 5 | 2019-08-01 | | 1 | 3 | 6 | 2019-08-02 | | 2 | 7 | 7 | 2019-08-01 | | 2 | 7 | 6 | 2019-08-02 | | 4 | 7 | 1 | 2019-07-22 | | 3 | 4 | 4 | 2019-07-21 | | 3 | 4 | 4 | 2019-07-21 | +------------+-----------+-----------+------------+
Result table: +------+ | id | +------+ | 5 | | 6 | +------+ ```
sql
SELECT DISTINCT viewer_id AS id
FROM Views
GROUP BY view_date, viewer_id
HAVING COUNT(DISTINCT article_id) >= 2
ORDER BY viewer_id