问Django Rest Framework使用PageNumberPagination类添加页码属性
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Stack Overflow用户

提问于 2017-10-08 02:27:49

回答 5查看 4.6K关注 0票数 5

我正在使用Django和Django rest框架构建一个API，并尝试在json结果上添加页码。我正在尝试在返回的结果中添加页码，例如，我现在得到了这个；

{
  "links": {
    "next": null,
    "previous": null
  },
  "count": 1,
  "results": [
    {
      "url": "http://127.0.0.1:8000/api/brands/1/?format=json",
      "name": "microsoft",
      "description": "Nothing",
      "top_brand": true,
      "guid": "microsoft"
    }
  ]
}

但是我正在试着得到这样的东西；

{
  "count": 1,
  "results": [
    {
      "url": "http://127.0.0.1:8000/api/brands/1/?format=json",
      "name": "microsoft",
      "description": "Nothing",
      "top_brand": true,
      "guid": "microsoft"
    },
    ...
  ],
  "page_number": 1,
  "from": 1,
  "to": 10,
  "last_page": 4
}

最重要的属性是page_number，但我不太确定如何使用self...从父类获取它，除了使用函数之外，我看不到任何直接的方法。这是我的代码；

class StandardResultsSetPagination(PageNumberPagination):
    page_size = 100
    page_size_query_param = 'page_size'
    max_page_size = 1000

    def get_paginated_response(self, data):
        return Response({
            'links': {
                'next': self.get_next_link(),
                'previous': self.get_previous_link()
            },
            'count': self.page.paginator.count,
            'results': data,
            'page_number': self.page.paginator...,
        })

python

json

django

django-rest-framework

回答 5

Stack Overflow用户

发布于 2017-10-08 02:58:41

您可以在视图集中使用自定义分页，也可以在自定义视图上进行更改

pagination.py

class CustomPageNumber(pagination.PageNumberPagination):
    page_size = 2

    def get_paginated_response(self, data):
        return Response(OrderedDict([
             ('lastPage', self.page.paginator.count),
             ('countItemsOnPage', self.page_size),
             ('current', self.page.number),
             ('next', self.get_next_link()),
             ('previous', self.get_previous_link()),
             ('results', data)
         ]))

在您的视图中

class TestViewSet(viewsets.ReadOnlyModelViewSet):
    queryset = Test.objects.all().order_by('-created_at')
    serializer_class = TestSerializer

    @list_route(methods=['get'], url_path='get-records/(?P<pk>[^/]+)')
    def get_record(self, request, pk):
        self.pagination_class = CustomPageNumber
        queryset = self.filter_queryset(self.queryset.filter(course=pk))
        page = self.paginate_queryset(queryset)
        if page is not None:
            serializer = self.get_serializer(page, many=True)
            return self.get_paginated_response(serializer.data)
        serializer = self.get_serializer(queryset, many=True)
        return Response(serializer.data)

REST_FRAMEWORK = {
    'DEFAULT_PAGINATION_CLASS': 'my_project.apps.core.pagination.CustomPageNumber',
    'PAGE_SIZE': 100
}

如果您想了解更多信息，请参阅文档custom-pagination-class

票数 12

Stack Overflow用户

发布于 2017-10-09 04:09:43

如果我没记错的话，你可以用self.page.number

    return Response({
        'links': {
            'next': self.get_next_link(),
            'previous': self.get_previous_link()
        },
        'count': self.page.paginator.count,
        'results': data,
        'page_number': self.page.number,
        #              ^^^^^^^^^^^^^^^^
    })

票数 4

Stack Overflow用户

发布于 2021-03-31 09:35:30

我认为像这样获得to和from可能更适用：

class MyCustomPagination(pagination.PageNumberPagination):

    def get_from(self):
        return int((self.page.paginator.per_page * self.page.number) - self.page.paginator.per_page + 1)

    def get_to(self):
        return self.get_from() + int(len(self.page.object_list)) - 1

    def get_paginated_response(self, data):

        return Response({
            'next': self.get_next_link(),
            'previous': self.get_previous_link(),
            'count': self.page.paginator.count,
            'total_pages': self.page.paginator.num_pages,
            'page_number': self.page.number,
            'per_page': self.page.paginator.per_page,
            'from': self.get_from(),
            'to': self.get_to(),
            'results': data
        })