如何找到带有numpy的Wronskian行列式
如何找到带有numpy的Wronskian行列式
提问于 2021-04-21 17:59:29
我试图找到这3个函数的Wronskian行列式，但代码中有"TypeError:找不到与指定签名匹配的循环，并且为ufunc det找到了类型转换“。我该怎么解决它呢？
import numpy as np
import numpy.linalg
import sympy as sp
x = sp.Symbol('x')
e=sp.exp(-3*x) #inputs
f=sp.cos(2*x)
g=sp.sin(2*x)
buneya=np.array([e,f,g],dtype=object)
a=sp.diff(buneya[0]) #first derivative
b=sp.diff(buneya[1])
c=sp.diff(buneya[2])
k=sp.diff(a)
l=sp.diff(b) #second derivative
m=sp.diff(c)
wronskian=np.array([[e,f,g],[a,b,c],[k,l,m]],dtype=object)
print (np.linalg.det(wronskian) ) #determinantTraceback (most recent call last):
File "C:\Users\canat\.spyder-py3\temp.py", line 20, in <module>
print (np.linalg.det(wronskian) )
File "<__array_function__ internals>", line 5, in det
File "C:\ProgramData\Anaconda3\lib\site-packages\numpy\linalg\linalg.py", line 2159, in det
r = _umath_linalg.det(a, signature=signature)
TypeError: No loop matching the specified signature and casting was found for ufunc det 回答 1
Stack Overflow用户
发布于 2021-04-21 18:09:22
就是这么简单：
import sympy as sp
x = sp.Symbol('x')
e=sp.exp(-3*x) #inputs
f=sp.cos(2*x)
g=sp.sin(2*x)
buneya=[e,f,g]
a=sp.diff(buneya[0]) #first derivative
b=sp.diff(buneya[1])
c=sp.diff(buneya[2])
k=sp.diff(a)
l=sp.diff(b) #second derivative
m=sp.diff(c)
wronskian=sp.Matrix([[e,f,g],[a,b,c],[k,l,m]]).det()
print(wronskian)返回
26*exp(-3*x)*sin(2*x)**2 + 26*exp(-3*x)*cos(2*x)**2有关更多信息，请参阅渐近矩阵docs。
编辑#1甚至更简单！
import sympy as sp
from sympy.matrices import dense
x = sp.Symbol('x')
e=sp.exp(-3*x) #inputs
f=sp.cos(2*x)
g=sp.sin(2*x)
wronskian = dense.wronskian([e,f,g],x)
print(wronskian)返回相同的
26*exp(-3*x)*sin(2*x)**2 + 26*exp(-3*x)*cos(2*x)**2wronskian方法也被记录在渐近docs中。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/67201194
复制相关文章
相似问题
腾讯云开发者
