从URL中删除重复的GET参数

# 伪代码示例，具体语法取决于编程语言和开发环境

# 1. 解析URL，获取参数部分
url = "http://www.example.com/?param1=value1&param2=value2&param1=value3"
params_start_index = url.find("?") + 1
params = url[params_start_index:]

# 2. 分割参数字符串，获取键值对列表
param_pairs = params.split("&")

# 3. 创建字典来存储参数键值对
param_dict = {}
for pair in param_pairs:
    key, value = pair.split("=")
    if key not in param_dict:
        param_dict[key] = []
    param_dict[key].append(value)

# 4. 构建去重后的参数字符串
filtered_params = []
for key, values in param_dict.items():
    for value in values:
        filtered_params.append(key + "=" + value)
filtered_params_str = "&".join(filtered_params)

# 5. 构建最终的URL
filtered_url = url[:params_start_index] + filtered_params_str

# 输出结果
print(filtered_url)