使用OpenCV和Python将一个圆划分为12个相等的部分

import cv2
import numpy as np

image = np.zeros((500, 500, 3), dtype=np.uint8)  # 创建500x500大小的空白图像
center = (250, 250)  # 圆心坐标
radius = 200  # 圆的半径
color = (0, 255, 0)  # 圆的颜色，这里使用绿色 (0, 255, 0)
thickness = -1  # 圆的填充，-1表示填充整个圆
cv2.circle(image, center, radius, color, thickness)  # 绘制圆

for i in range(12):
    angle_start = i * 30  # 每个划分点的起始角度
    angle_end = (i + 1) * 30  # 每个划分点的结束角度

    start_point = (int(center[0] + radius * np.cos(np.radians(angle_start))),
                   int(center[1] + radius * np.sin(np.radians(angle_start))))  # 起始点坐标
    end_point = (int(center[0] + radius * np.cos(np.radians(angle_end))),
                 int(center[1] + radius * np.sin(np.radians(angle_end))))  # 结束点坐标

    cv2.line(image, center, start_point, color, 2)  # 绘制从圆心到起始点的线段
    cv2.line(image, center, end_point, color, 2)  # 绘制从圆心到结束点的线段
    cv2.line(image, start_point, end_point, color, 2)  # 绘制起始点到结束点的线段

cv2.imshow("Circle Divided", image)  # 显示图像
cv2.waitKey(0)  # 等待按键退出
cv2.destroyAllWindows()  # 关闭窗口