我正在尝试查找下表中每年出现次数最多的收件人: user_ID (msgID,user_ID,time_read)SELECT DISTINCT EXTRACT(YEAR FROMtime_read) as years FROM RecipientsSELECT user_ID u, cnt FROM(SELECTEXTRA
我有这个SQL查询,它可以做我想做的事情,但我对GroupBy()和OrderBy()的确切工作方式感到困惑……SELECT TOP 5 UserID, COUNTOR SkillID = 102 OR SKILLID = 103 ORDER BY COUNT(*) DESC
理想情况下,最终产品是一个满足这些条件的UserID列表,按每个SkillID的出现次数排序,其中匹配Sk