如何允许url字符串更改使用express创建REST API时返回的JSON消息？

const express = require('express');
const app = express();
const port = 3000;

// 模拟数据
const users = [
  { id: 1, name: 'Alice', age: 25 },
  { id: 2, name: 'Bob', age: 30 },
  { id: 3, name: 'Charlie', age: 35 }
];

// 路径参数示例
app.get('/users/:id', (req, res) => {
  const userId = parseInt(req.params.id);
  const user = users.find(u => u.id === userId);
  if (user) {
    res.json(user);
  } else {
    res.status(404).json({ message: 'User not found' });
  }
});

// 查询参数示例
app.get('/users', (req, res) => {
  const { name, age } = req.query;
  let filteredUsers = users;

  if (name) {
    filteredUsers = filteredUsers.filter(user => user.name.toLowerCase().includes(name.toLowerCase()));
  }

  if (age) {
    filteredUsers = filteredUsers.filter(user => user.age === parseInt(age));
  }

  res.json(filteredUsers);
});

app.listen(port, () => {
  console.log(`Server is running on http://localhost:${port}`);
});

const userId = parseInt(req.params.id);
if (isNaN(userId)) {
  return res.status(400).json({ message: 'Invalid user ID' });
}

if (!req.query.name && !req.query.age) {
  return res.status(400).json({ message: 'At least one parameter is required' });
}