我有一个表,它有20个整数列和1个文本列,名为'foo‘SELECT * from table_name where foo is NULLERROR: column "foo" does not existSELECT * from table_name where count is NULL感谢您的帮助(POSTGRESQL 8.3)
我有03-AUG-12 08.15.00.000000000 PM -05:00形式的时间戳,我无法在yyyy-MM-dd HH:mm:ss上获得String表示形式。public static void convert() {
Date date = null; date = new SimpleDateFormat("dd-MMM-yy HH.mm.ss.S aa"