如何在ajax参数中传递$( select2 ) of select2

<select id="mySelect2">
  <option value="1">Option 1</option>
  <option value="2">Option 2</option>
  <option value="3">Option 3</option>
</select>

var selectedValues = $('#mySelect2').val();

$.ajax({
  url: 'your_url',
  type: 'POST',
  data: {
    selectedValues: selectedValues
  },
  success: function(response) {
    // 处理成功响应
  },
  error: function(xhr, status, error) {
    // 处理错误响应
  }
});