lib/python3.6/dist-packages/geolocation/validators.py", line 46, in validate_google_statusgeolocation.exceptions.ApiClientException: Request was denied.
methodArgs);catch (Exception e) // Here I was hoping to get an error code.当我调用上面的WMI方法时,我预计会被拒绝访问在catch块中,我希望确保引发的异常确实是因为访问被拒绝。有没有办法可以得到它的错误代码?拒绝访问的Win32错误代码是5。我不想在错误消息中搜索拒绝字符串或类似的内容。
谢谢