扩展jQuery post功能

$.ajax({
  url: 'example.php',
  type: 'POST',
  data: {
    name: 'John',
    age: 30
  },
  success: function(response) {
    console.log('Request successful');
  },
  error: function(xhr, status, error) {
    console.error('Request failed');
  }
});