比如: initdb -E EUC_JP 把缺省字符集设置为EUC_JP(用于日文的扩展Unix 编码)。如果你喜欢用长选项字符串,你可以用–encoding代替-E。...=ko_KR.euckr korean 将创建一个使用EUC_KR字符集和ko_KR区域的名为korean的数据库。...假如无法进行一个特定字符的转换 — 假如你选的服务器编码是EUC_JP而 客户端是LATIN1,那么有些日文字符不能转换成LATIN1 — 将会报告一个错误。...CJKV Information Processing: Chinese, Japanese, Korean & Vietnamese Computing 包含对EUC_JP、 EUC_CN、EUC_KR...、 EUC_TW的详细解释。
IBM905 IBM EBCDIC Turkish 20924 IBM00924 IBM EBCDIC Latin 1/Open System (1047 + Euro symbol) 20932 EUC-JP...EBCDIC US-Canada and Traditional Chinese 50939 EBCDIC Japanese (Latin) Extended and Japanese 51932 euc-jp...EUC Japanese 51936 EUC-CN EUC Simplified Chinese; Chinese Simplified (EUC) 51949 euc-kr EUC Korean 51950...EUC Traditional Chinese 52936 hz-gb-2312 HZ-GB2312 Simplified Chinese; Chinese Simplified (HZ) 54936
在日常工作中,常用的SAS语言环境有三个,即英文(wlatin1 western),简体中文(euc-cn),Unicode(utf-8)。...首先,我们需要掌握两个原理: 不同编码涵盖的字符量:utf8>euc-cn>wlatin1。这表明,从utf8往下转码时。只有在字符适用时才成功。...不同编码多字节字符占据的字节数量:utf8(3 bytes)>euc-cn(2 bytes)>wlatin1(1 byte)。...在下面的代码中,l3变量存在euc-cn不能识别的字符,l2变量存在wlatin1不能识别的字符,l变量的字符,三种编码均能识别。 ? ? ?...euc-cn打开其他两种编码的.sas文件: ? ? utf8打开其他两种编码的.sas文件: ? ? 由此可见。不论字符能不能识别。只要用sas编辑器,打开其他编码的.sas文件。就会产生乱码。
EUC_JP JISX 0201, 0208 and 0212, EUC encoding Japanese x-EUC-JP-Linux EUC_JP_LINUX JISX 0201, 0208 ,...EUC encoding Japanese Shift_JIS SJIS Shift-JIS, Japanese ISO-2022-JP ISO2022JP JIS X 0201, 0208, in...EUC_CN GB2312, EUC encoding, Simplified Chinese GBK GBK GBK, Simplified Chinese ISCII91 ISCII91 ISCII91...encoding of Indic scripts x-windows-949 MS949 Windows Korean EUC-KR EUC_KR KS C 5601, EUC encoding,...EUC_TW CNS11643 (Plane 1-3), EUC encoding, Traditional Chinese Big5 Big5 Big5, Traditional Chinese Big5
在euc-cn编码下,多字节字符占据2字节。这里,L变量长度是11,L2变量长度是16. ? 在utf-8编码下,多字节字符占据3字节。这里L变量长度是12,L2变量是24,L3变量是8。...我们用euc-cn的编辑器,读取utf-8编码的数据集(A3)时,发生了错误。跟上一个操作类似,存在无法识别的字符。 那么,我们先把UTF-8编码的数据集的特殊字符(A3.L3)变量去掉,会如何呢?...我们用utf-8的编辑器,读取euc-cn编码的数据集(A2)时,发生了错误。...因为在euc-cn编码下,L变量和L2变量需要的长度分别为11和16;而在utf-8编码下,L变量和L2变量需要的长度则是12和24。变量不够长了,将会截断。 ?
Recently, a company named EUC (Exploring the Unknown Company) plan to explore an unknown place on Mars...For fast development of technology and bad environment for human beings, EUC sends some robots to explore...For financial reason, EUC wants to use minimal number of robots to explore all the points on Mars. ...As an ICPCer, who has excellent programming skill, can your help EUC?
In Qt the supported encodings are: Apple Roman Big5 Big5-HKSCS CP949 EUC-JP EUC-KR GB18030-0 IBM 850
欧氏距离 pca = decomposition.PCA(n_components=2) pca.fit(df_man_dist_euc) df_fc_cleaned_reduced_euc =...pd.DataFrame(pca.transform(df_man_dist_euc).transpose(),...axis limits for the silhouette plot ax1.set_xlim([-0.1, 1]) ax1.set_ylim([0, len(df_man_dist_euc...n_clusters, n_init="auto", random_state=10) cluster_labels = clusterer.fit_predict(df_man_dist_euc...().iloc[:, 0], df_fc_cleaned_reduced_euc.transpose().iloc[:, 1], marker="
-o lang=euc-jp|euc-tw|euc-kr|shift-jis|big5|ksc5601|gb2312-80|ansi 指定用于文件和目录名称的编码
plain;charset=UTF-8 Content-Length: 72 Connection: keep-alive Accept-Charset: big5, big5-hkscs, cesu-8, euc-jp..., euc-kr, gb18030, gb2312, gbk, ibm-thai, ibm00858, ibm01140, ibm01141, ibm01142, ibm01143, ibm01144,..., x-euc-tw, x-eucjp-open, x-ibm1006, x-ibm1025, x-ibm1046, x-ibm1097, x-ibm1098, x-ibm1112, x-ibm1122..., euc-kr, gb18030, gb2312, gbk, ibm-thai, ibm00858, ibm01140, ibm01141, ibm01142, ibm01143, ibm01144,..., x-euc-tw, x-eucjp-open, x-ibm1006, x-ibm1025, x-ibm1046, x-ibm1097, x-ibm1098, x-ibm1112, x-ibm1122
zh_CN.UTF-8 "language message zh_CN.UTF-8 "set fileencodings=ucs-bom,utf-8,gb18030,cp936,big5,euc-jp...,euc-kr,latin1 endif "Enable filetype plugin filetype plugin on filetype indent on "Set to auto read...,euc-kr,latin1 " CJK environment detection and corresponding setting if v:lang =~ "^zh_CN" " Use... set termencoding=euc-kr set fileencoding=euc-kr elseif v:lang =~ "^ja_JP" " Copied from...someone's dotfile, untested set encoding=euc-jp set termencoding=euc-jp set fileencoding=
JIS-允许一个字节的片假名) 50222 日文(JIS-允许一个字节的片假名 - SO/SI) 50225 韩文(ISO) 50932 日文(自动选择) 50949 韩文(自动选择) 51932 日文(EUC...) 51949 韩文(EUC) 52936 简体中文(HZ) 65000 Unicode (UTF-7) 65001 Unicode (UTF-8)
、ASCII码 字符对应关系 2、汉字编码 ——GBK 3、日文编码 ——Shift_JIS 4、韩文编码 ——EUC-KR 5、万国码 ——Unicode Unicode简介: UTF-8 字符编码实操...4、韩文编码 ——EUC-KR 为了能够让计算机识别韩文,需要发明一套编码表, EUC_KR编码表记录了韩文英文与数字的对应关系。
CSISO58GB231280 CN-GB-ISOIR165 ISO-IR-165 ISO-IR-149 KOREAN KSC_5601 KS_C_5601-1987 KS_C_5601-1989 CSKSC56011987 EUC-JP...SHIFT_JIS SJIS CSSHIFTJIS CP932 ISO-2022-JP CSISO2022JP ISO-2022-JP-1 ISO-2022-JP-2 CSISO2022JP2 CN-GB EUC-CN...CSGB2312 GBK CP936 MS936 WINDOWS-936 GB18030 ISO-2022-CN CSISO2022CN ISO-2022-CN-EXT HZ HZ-GB-2312 EUC-TW...BIG5 BIGFIVE CN-BIG5 CSBIG5 CP950 BIG5-HKSCS:1999 BIG5-HKSCS:2001 BIG5-HKSCS BIG5-HKSCS:2004 BIG5HKSCS EUC-KR...IBM863 CSIBM863 CP864 IBM864 CSIBM864 865 CP865 IBM865 CSIBM865 869 CP-GR CP869 IBM869 CSIBM869 CP1125 EUC-JISX0213
Adobe-Standard-Encoding Big5=Big5 Big5-HKSCS=Big5-HKSCS BOCU-1=BOCU-1 CESU-8=CESU-8 cp1363=cp1363 cp851=cp851 EUC-JP...=EUC-JP EUC-KR=EUC-KR GB18030=GB18030 GBK=GBK hp-roman8=hp-roman8 HZ-GB-2312=HZ-GB-2312 IBM-Thai=IBM-Thai...windows-1257 windows-1258=windows-1258 x-compound-text=x-compound-text x-ebcdic-xml-us=x-ebcdic-xml-us x-euc-tw...-2014=x-euc-tw-2014 x-gsm-03.38-2009=x-gsm-03.38-2009 x-ibm-1047-s390=x-ibm-1047-s390 x-ibm-1125_P100
PostgreSQL 中的字符集支持允许以各种字符集(也称为编码)存储文本,包括单字节字符集,如 ISO 8859系列和多字节字符集,如 EUC (EUC)、 UTF-8和 Mule 内部代码。
: eil51 COMMENT : 51-city problem (Christofides/Eilon) TYPE : TSP DIMENSION : 51 EDGE_WEIGHT_TYPE : EUC...但是需要注意的是,EDGE_WEIGHT_TYPE并不是只有EUC_2D一种,而是有13种之多。各种类型有对应的距离计算方法,如曼哈顿距离,地理距离等,这里我就不一一列举了,论文中有详细的叙述。
ISO-2022-CN /usr/share/xpdf/xpdf-chinese-simplified/ISO-2022-CN.unicodeMap unicodeMap EUC-CN... /usr/share/xpdf/xpdf-chinese-simplified/EUC-CN.unicodeMap unicodeMap GBK
本文使用欧氏距离计算坐标之间的距离: //计算projected_test与projected_train中每个向量的欧氏距离 Euc_dist = (double *)malloc(sizeof...[i] = temp; //printf("%f \n",temp); } //寻找最小距离 double min = Euc_dist[0]; int label; for (i=0;...i<TRAIN_NUM;i++) { if (min>=Euc_dist[i]) { min = Euc_dist[i]; label = i; } } printf("%...[i] = temp; //printf("%f \n",temp); } //寻找最小距离 double min = Euc_dist[0]; int label; for (i=0...;i<TRAIN_NUM;i++) { if (min>=Euc_dist[i]) { min = Euc_dist[i]; label = i; } } printf("