我有一个返回数据列表的api。当我检索数据时,我使用FutureBuilder来显示数据列表。但是由于某些原因,它不会显示我的数据,即使当我打印响应时,我可以看到我得到了正确的响应。I/flutter (11846): The offending widget is: FutureBuilder<List<BasicDiskInfo>>
I/flutter (11846): BuildTo return an
extends StatelessWidget { Widget build(BuildContext context) {Error: A non-null value must be returned since the return type 'Widget' doesn't allow null.- 'Widget' is from 'package:flutter/src&
I/flutter ( 8804): When an inherited widget changes, for example if the value of Theme.of() changes,If the dependent widget's reference to the inherited widget is in a constructor
I/flutter ( 8804): oran initState() method, then the rebuilt
如果数据库中存在数据,则返回我的api返回号;如果不存在,则返回null。(),There should be exactly one item with [DropdownButton]'s valueEither zero or 2 or more [DropdownMenuItem]s were detected with the same value
'package:<
这是我的壁球俱乐部的本地球场预订网站,从我所看到的情况来看,这是它调用的检索球场预订的JavaScript脚本: var e = document.createElement}
setInterval("load_js('/js/bookings_reload.js.php')", 30000);我怎么才能在Flutter我可以抓取HTML并解析它来创建一个HTML文档,但是由于<
A widget can be marked I/flutter ( 8918): only if oneI/flutter ( 8918): Otherwise, the framework might not visit this
widget during this build phase.I/flutter ( 8918): The widget on w