$result = mysql_query("SELECT * FROM Places WHERE Location = '$location' and Type ='$type' and Rating= '$rating'")如果用户从所有3个下拉框中选择和选项,这将工作得很好-但是,如果用户只选择一个位置,我如何使msql查询检查数据库。我在所有3个下拉列表上都有一个"Any“选项
如何通过这个查询实现我想要的:(SELECT id FROM posts order by timestamp desc limit当我尝试这个查询时,我就明白了。MySQL还不支持“限制”& IN/ALL/ANY/SOME子查询mySQL Server version: 5.5.8
mySQL Client version: mysqlnd 5.0.7
在环顾四周并按照在上给出的答案后,我尝试了这个查询。book.id IN (SELECT book.id FROM book ORDER BY rating LIMIT 3) #1235 - This version of MySQLdoesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'
解决方案说需要最少的MySQL 5.1,我正在运行libmysql - 5.1.73
ERROR: index 'dk_delta': sql_range_query: 'example.com.p.post_title' isn't in GROUP BY (DSN=mysql://dekanta_flyus3rERROR: index 'dk_main': sql_range_query: 'example.com.p.post_title' isn't in GROUP BY (DSN=mysql:/
我正在创建查询计数表。DATE_FORMAT(ANY_VALUE(TIME), '%Y-%m') AS `Month` WHERE DATE_FORMAT(TIME, '%Y-%m')='$Month' 它在MySql版本中的工作是5.7.10 (本地主机)。函数server_dbname.ANY_VALUE不存在’在.中
目前我正在使用MySQL5.7进行开发,5.6处于生产阶段。每次在开发中使用GROUP BY运行查询时,我都会得到一些错误,如"Error Code: 1055.Expression #1 of SELECT list is not in group by“ ANY_VALUE(i.lat) lat, FROM countries c, images iWHERE i.count