SELECT PRODUCT.id, SUM(PRODUCTION.quantity)LEFT JOIN PRODUCTION ON PRODUCT.id = PRODUCTION.product_idGROUP BY PRODUCT.id 对比 SELECT (SELECTSUM(quantity)
FROM PRODUCTION
我想写一段代码,从没有JOIN关键字的查询中提取表名和列名。而是使用笛卡尔连接(,),如下所示:FROM suppliers(SELECT supplier_id, SUM(orders.amount) AS total_amtGROUP BY supplier_id) subquery1
WHERE subquery1.suppli
嗨,我需要用Zend_Db_Select写这个sql,但我不知道如何写子查询。如果有任何帮助,我将不胜感激。谢谢。SELECT * FROM advert WHERE categoryId SELECT id WHERE `lft` BETWEEN
(SELECT lft FROM tree WHERE id = '2'
我正在寻找一种基于子subselect在多个值上运行"locate“函数的方法;这是我所设想的伪代码(它不运行,因为子subselect返回多个值;这正是我想要的)。select * from table这是一个未知数的值,因此我不能使用with cte_subselect as (select distinct field
我有如下所示的sql查询-district, coalesce(sell.sale,0) as totalsale left join
(SELECTparties_district, billdate, sum(billamount) as sale FROM `bills` left join parties on bills.bills_partynameparties_district, billdate, sum
通常我们使用SELECT MAX(datetime)和GROUP BY(page_ID)来获取最新的页面,但我不明白为什么它不能在这里工作。下面的查询应该只选择ID为75和77的行,但它选择的是75和76行:
SELECT ru.page_ID AS id, UNIX_TIMESTAMPru.current_rank AS current_rank, FROM ranks_update ru
我有一张这样的桌子: Name | Surname | Grade Alex | Smith | A Sean | Colon | CLaurence | Bryant | DGracie | Coates | C
Kenneth | Khan | A 我想选择同级学生的姓名、年级和人数,所以结果应该是这样的: Name | Su
当我的mysql服务器有非常大的查询时(我不知道确切的查询数),它会重新启动。所以我在想在表演中。(我正在使用SELECT * from testing proposes)SELECT * FROM devicesApps WHERE appID='$idApp' anddeviceID IN (SELECT id FROM devices WHERE fingerprint='$fingerprint')SELECT</em