我试图得到提交的总数,我想要两个结果,一个具有特定状态的提交,一个具有所有状态:
SELECT submissions.campid,
COUNT(submissions.id) AS subsCountTotal,
(SELECT COUNT(submissions.id)
FROM submissions,campaings
WHERE submissions.campid = campaings.id
AND campaings.status = 1
and submissions.t
所以我想在我的web应用程序中使用Devise,在本地主机上测试一切正常,但是当我将它上传到我的ec2实例时,我得到了错误‘No route matches get "/“’,我不知道如何解决这个问题。
这是我的Routes.rb:
devise_for :users
resources :submissions
root to: 'home#index'
scope "api" do
get "/submissions(.:format)" => "submissions#index"
get "/s
当我运行一个简单地执行get :index的测试时,我得到了这个错误。下面是测试代码:
class SubmissionsControllerTest < ActionController::TestCase
setup do
@submission = submissions(:one)
end
test "should get index" do
get :index
assert_response :redirect
# assert_not_nil assigns(:submissions)
end
我在我的rou
我有一个计算点击量和提交数的MySQL查询。然后我想计算出有多少点击成为提交的比率。下面的查询给出了我想要的结果:
SELECT
clicks.review_id,
COUNT(clicks.id) as clicks,
COUNT(submissions.id) as submissions,
ROUND((((COUNT(submissions.id))/(COUNT(clicks.id)))*100),1) as rate,
submissions / clicks as other
FROM submissions
RIGHT JOIN clicks ON clicks.id = su
如何将mysql查询转换为laravel查询?这就是查询
SELECT
users.first_name,
users.id AS uid,
(
SELECT
COUNT(vpl_submissions.accept)
FROM
vpl_submissions
INNER JOIN vpl ON vpl_submissions.vpl = vpl.id
WHERE vpl.courseid = 2
AND vpl_submissions.accept = 1
AND vpl_submissions.userid = uid
) A
我有一个SQL查询,我使用向导创建了这个查询,然后稍微修改了一下。此查询需要从同一个工作簿中的两个工作表中提取数据。下面是我稍微修改过的代码:
SELECT `'TA Submissions$'`.`TA Content`, `'TA Submissions$'`.`Subject of TA`, `'TA Submissions$'`.`Unit of TA`, `'TA Submissions$'`.`Title of TA`, `'TA Submissions$'`.`Any Notes for the In
我想对不同的内容进行情感分析,并考虑“新”和“热”的意见。我可以通过以下方式做到这一点:
# What I have
def new_submissions(sub):
subreddit = reddit.subreddit(sub).new(limit=100)
for submission in subreddit:
# Do stuff
return new_stuff
def hot_submissions(sub):
subreddit = reddit.subreddit(sub).hot(limit=100)
for submissi
我想生成一个10个最近提交的列表-但来自不同的用户。
我现在做的是这样的:
unique_users = []
submissions_from_different_users = []
submissions = Submission.objects.all().order_by('-date')
for submission in submissions:
if len( submissions_from_different_users ) == 10:
break
if not submission.user in unique_user
使用MySQL和我应该返回缺席人数和他们的名字。我为所有的学生做了一个查询,并减去了那天出现的学生的子查询。
在1次查询中甚至可以这样做吗?我知道如何使用两个单独的语句,它们返回不同大小的语句,所以我不确定它们是否兼容。
姓名清单:
select distinct name
from submissions join hacker
on submissions.hacker_id=hacker.hacker_id
where name not in
(
select distinct name
from submissions join hacker
on submissions.ha
我一直在使用指南开发Drupal7模块。
我希望这个模块可以简单地将它们显示给管理员,然后管理员可以从那里更改和接受它们。我可以让我的模块出现在Modules部分,但是当我启用它时,我构建的表单和菜单项并不在它们应该出现的位置。配置部分中没有菜单项,因此我无法导航到我创建的表单。这是我的.module:
/**
* Implements hook_help.
*
* Displays help and module information.
*
* @param path
* Which path of the site we're using to display help
*
给定以下模式..。
如何将以下查询转换为使用联接(使用MySQL)?
SELECT submissions.SubmissionID,
(SELECT data.DataContent FROM data WHERE data.DataFieldName =
(SELECT forms.FormEmailFieldName FROM forms WHERE forms.FormID = submissions.SubmissionFormID)
AND data.DataSubmissionID = submissions.SubmissionID) AS EmailAddres