在分析Alpha-beta剪枝算法的失败-硬版本和失败-软版本时,我找不到它的行为上的区别:function alphabeta(node, depth, α, β, maximizingPlayermaximizingPlayer then for each child of node do else for each child o
bestMoveVal = Math.max(bestMoveVal, eval); return bestMoveVal;}public int alphabetaeach max player's moves) { int eval = alphabetafor(each of min's moves) {
例如,我的alphabeta()在下面的伪..。public int alphabeta(int depth, Board b, int alpha, int beta, boolean maxPlayer) { for(each of min's moves) { int eval = alphabeta本质上,evaluateBoard()给出了<e