right_answer = capitals[provinces[index]] # 2....然后,将这个名字作为 capitals 字典的 key,读取 capitals[provinces[index]] 就得到省会城市名,将它赋值给 right_answer。...在第2步中,使用 capitals.values() 读取 capitals 的所有城市名,再将它转成列表类型,赋值给wrong_answer变量。...right_answer = capitals[provinces[index]] # 2....这行代码的三部分分别做了前面所说的三件事情: 1、从 capitals 中确定当前编号所对应省的省会城市:capitals[provinces[i]]。
问题(Easy): Given a word, you need to judge whether the usage of capitals in it is right or not....We define the usage of capitals in a word to be right when one of the following cases holds: All letters...in this word are capitals, like "USA"....All letters in this word are not capitals, like "leetcode"....Otherwise, we define that this word doesn't use capitals in a right way.
题目描述: Given a word, you need to judge whether the usage of capitals in it is right or not....We define the usage of capitals in a word to be right when one of the following cases holds: All letters...in this word are capitals, like "USA"....All letters in this word are not capitals, like "leetcode"....Otherwise, we define that this word doesn't use capitals in a right way.
Given a word, you need to judge whether the usage of capitals in it is right or not....We define the usage of capitals in a word to be right when one of the following cases holds: All letters...in this word are capitals, like “USA”....All letters in this word are not capitals, like “leetcode”....Otherwise, we define that this word doesn’t use capitals in a right way.
Properties 类 // Properties : k v 都是字符串的 Hashtable Properties capitals = new Properties();...capitals.put("中国", "北京"); capitals.put("日本", "东京"); // capitals.put("美国", "华盛顿");...Set states = capitals.keySet(); String country; Iterator it4 = states.iterator();...hasNext()){ country = (String) it4.next(); System.out.println(country + " : " + capitals.getProperty...(country)); } String str = capitals.getProperty("美国", "not found");//若没有key,返回默认值 not
今天和大家聊的问题叫做 检测大写字母,我们先来看题面: https://leetcode-cn.com/problems/detect-capital/ We define the usage of capitals...in a word to be right when one of the following cases holds: All letters in this word are capitals,...All letters in this word are not capitals, like "leetcode"....Given a string word, return true if the usage of capitals in it is right.
下面是一个使用上述方法实现的测验程序代码示例:import randomdef main(): capitals = { "Washington": "Olympia",...Baton Rouge", } wrong = [] print("STATE TEST\n") incorrect_answers = False while len(capitals...) > 0: pick = random.choice(list(capitals.keys())) correct_answer = capitals.get(pick)...\n") del capitals[pick] else: print("That's Incorrect.")
{italic} 细体字:\textlf{light font} 使用等宽字体:\texttt{code} 使用无衬线字体:\textsf{sans-serif} 所有字母大写:\uppercase{CAPITALS...} 所有字母大写,但小写字母比较小:\textsc{Small Capitals} 发布者:全栈程序员栈长,转载请注明出处:https://javaforall.cn/168283.html原文链接:https
/bin/bash R=70/138/13/56 J=M105/35/6.5i PS=CN-capitals.ps gmt set MAP_GRID_PEN_PRIMARY 0.25p,gray,2_...-J$J -R$R -Sc0.08c -Gblack -K -O >> $PS gmt psxy CN-capitals.dat -J$J -R$R -Sc0.15c -W0.2p,black -K...-O >> $PS # 绘制省会名称 gmt pstext CN-capitals.dat -J$J -R$R -F+f7p,35+j -Dj0.15c/0.15c -K -O >> $PS # 标记北京所在位置...0.1c -N -Gwhite -O >> $PS gmt psconvert -A -P -Tg $PS rm gmt.conf gmt.history $PS 执行: chmod +x CN-capitals.sh.../CN-capitals.sh 出图: 参考网站 GMT相关资源汇总. 表示感谢!
val capitals = Map("France" -> "Paris", "Japan" -> "Tokyo") def show(x: Option[String]) = x match { /...} scala> show(capitals get "France") res24: String = Paris scala> show(capitals get "North Pole") res25
让我们创建两个表:表cities和表capitals。自然地,首都也是城市,所以我们需要有某种方式能够在列举所有城市的时候也隐式地包含首都。...如果真的聪明,我们会设计如下的模式: CREATE TABLE capitals ( name text, population real, altitude int, -- (in ft) state...char(2) ); CREATE TABLE non_capitals ( name text, population real, altitude int -- (in ft) ); CREATE...FROM non_capitals; 这个模式对于查询而言工作正常,但是当我们需要更新一些行时它就变得不好用了。...( state char(2) ) INHERITS (cities); 在这种情况下,一个capitals的行从它的父亲cities继承了所有列(name、population和altitude)
: "https://countries.trevorblades.com/", cache: new InMemoryCache(), }); const GET_COUNTRIES_AND_CAPITALS...} } `; function CountriesList() { const { loading, error, data } = useQuery(GET_COUNTRIES_AND_CAPITALS...CountriesAndCapitals() { return ( Countries and Capitals
decimal import * >>>getcontext() Context(prec=28, rounding=ROUND_HALF_EVEN, Emin=-999999, Emax=999999, capitals
同样,有一种更通用的方法获得所需的结果,只需使用zip(),如以下代码所示: countries = ['France', 'Germany', 'Canada'] capitals = ['Paris...', 'Berlin', 'Ottawa'] for country, capital in zip(countries,capitals): print(country, capital)
Keys are states and values are their capitals....capitals变量 ➋ 包含一个字典,以美国各州为键,以它们的首都为值。...correctAnswer = capitals[states[questionNum]] # ➊ wrongAnswers = list(capitals.values()) # ➋...正确答案很容易得到——它作为一个值存储在capitals字典 ➊ 中。...复制capitals字典 ➋ 中的所有值,删除正确答案 ➌,从这个列表中选择三个随机值 ➍ 即可得到。random.sample()函数使选择变得容易。
decimal.getcontext() print 'Emax =', context.Emax print 'Emin =', context.Emin print 'capitals...=', context.capitals print 'prec =', context.prec print 'rounding =', context.rounding print
aware of a trademark claim, the designations have been printed in initial capital letters or in all capitals
val v5 = v3(5) set:元素无序,不能用下标访问,元素无重复 val fruits = Set("apple", "orange", "pear", "banana") 映射Map val capitals...", "UK" -> "London", "India" -> "New Delhi") val indiaCapital = capitals("India") 集合类的高阶方法:这是scala集合类真正强大的地方
= keyStream1.findFirst().get(); Stream keyStream2 = keys(capitalCountryMap, "South Africa"); Set capitals
示例: 创建一个cities表作为父表,然后创建一个capitals表作为子表,capitals继承自cities,并添加一个state列来表示州的缩写。...TABLE cities ( name text, population real, elevation int -- (in ft) ); CREATE TABLE capitals
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