我在这段代码中遇到了问题,我从两个表中获取信息,并且“news_id=$dz”不起作用。包含此代码的。<?php$result = mysql_query("SELECT dz,title FROM dzeglebi where raioni=id=%s'>%s</a>
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: java.io.IOException: Cannot run program "/private/var/folders/l5/4ywgvbbj1kvgvrwxzp6dz82c0000gn/T/test_db(Exceptions.java:55)
at com.mysql.management.util.Exceptions$Block.exec(Exceptions.java:89)at com.mysql.management.uti