当条件满足时,我正在尝试打印前一行。示例:abc.txt文件包含以下行
User 1 - I like eating Apple
User 2 - I like eating Apple
User 3 - I like eating Apple
User 4 - I like eating Grapes
User 5 - I like eating Apple
User 6 - I like eating Orange
如果我没有在行中找到"Apple“文本,那么我需要打印前一行”用户3-我喜欢吃苹果“和”用户5-我喜欢吃苹果“。
我试过的是:
with open('abc.t
我真的搞砸了这个问题。我有一个数据集: example = data.frame(age = c(34,19,44,22,34,12,54,63,23),
wash.hands = c("Before eating","Before eating, on public transportation","Before eating, After eating",
"After eating","on p
我试图通过限制吃4的哲学家的数量来解决哲学家问题。在main函数中,我像这样编写代码来创建线程。
for (i = 0; i < N; i++) {
pthread_create(&tidp[i], NULL, creatPhilosopher, (void *)&i);
}
但下面是输出
philosopher 0 is thinking...
philosopher 0 is thinking...
philosopher 0 is thinking...
philosopher 0 is thinking...
philosopher 0 i
考虑这个人为的例子:
# Dispatch on value of fruit_kind:
TYPE_A = :apple
TYPE_B = :banana
TYPE_C = :cherry
eating_method = nil
case fruit_kind
# Methods to use for different kinds of fruit (assume these are
# already defined)
when TYPE_A then eating_method = bite
when TYPE_B then eating_method = pe
这是我对Philosopher晚餐并发问题的实现。我只为两个线程工作,其余的都饿死了;)如果你能找到原因,我将不胜感激。
下面是输出:
Philosopher 2 is eating
Philosopher 0 is eating
Philosopher 2 is eating
Philosopher 0 is eating
Philosopher 2 is eating
Philosopher 0 is eating
Philosopher 2 is eating
Philosopher 0 is eating
Philosopher 2 is eating
Philosopher 2 is
我正在写一个应用程序,你按下不同的按钮,一个角色就会得到动画效果。问题是我有很多图像,所以我需要为每个动画使用一个纹理。因此我需要释放精灵表和框架现金,但它似乎不起作用。内存分配越来越多,直到应用程序崩溃。代码如下:
// **** DEFINE THE ANIMATION - EATING 1: ****
// Create a sprite sheet with all the images
CCSpriteSheet *spriteSheet = [CCSpriteSheet spriteSheetWithFile:@"Eating4.png"];
// This l
我有一个包含许多行的文件:
at 12:00 the schedule is :
first_task:eating:fruit
second_task:rest:onehour
third_task:watching:horrorfilm
at 18:00 the schedule is :
first_task:eating:vegetals
second_task:rest:threehours
third_task:watching:manga
at 22:00 the schedule is :
first_task:eating:nothing
second_tas
我正在创建一个表格,然后显示记录,这让我很好奇。
如果我存储,例如“饮食习惯”有一个制造(素食,非素食和鸡蛋),如果我把'eating_habits‘存储为一个int或tinyint或varchar或enum类型,会对查询速度产生什么影响。
使用int 方法1也是如此。
// to select records
SELECT * FROM table WHERE eating_habits = 2 AND ...;
//for display in php
foreach($all_records AS $key => $val) {
if($val['eati
我需要一个负的先行表达式,但是我不能让它工作:(我希望有人能帮助我。我需要一个表达式,它是真的,直到样本中的任何地方都不包含2个单词。例如,2个单词pie donuts:
i sure like eating pie, but i love donuts very much
---> false
i sure like eating but i love donuts very much
---> true
i sure like eating pie, but i love hamburger very much
---> true
i sure like eating d
例如,这是我的数据
info
----
id name eating andSaying
--- ---- ------ ---------
1 aman mango with sister amanzing mango
2 ramesh mango via mouth wow its really good
3 aman guava with jimmy yoyo
4 ramesh pineapple yum
我正试图创建一个列来确定食物消费的顺序,以知道什么时候是一顿饭的开始和结束。这样我就可以根据他们的饮食组成一个小组,知道他们吃了什么。
电流帧
Name DateTime Food Water Extra TimeofMeal Event
1 Alex 27/9/2020 10:25 Apple Null Null 27/9/2020 10:25 Start Eating
2 Alex 27/9/2020 10:50 Null 100 Null Null Null
3 Ale
我在将数组中的余弦相似性分配给熊猫Dataframe时遇到了问题。我使用下面的代码测试了余弦相似矩阵
# Find the closest 5 sentences of the corpus for each query sentence based on cosine similarity
top_k = min(5, len(corpus))
for query in queries:
query_embedding = model.encode(query, convert_to_tensor=True)
# We use cosine-similarity and t
我是新来的巴什命令。如何编写此脚本以获得如下输出?注意:我有两个文件。
file.txt:
i am going home
i am eating
He is working
patterns.txt:
going
eating
我希望在outputfile.txt中有以下内容:
i am going home
i am eating
我读到,set of运算符在Pascal中表示数学"",但我似乎不明白它是如何表示的。
例如,我有以下代码:
program setDemo(output);
type
skill = (cooking, cleaning, driving, videogames, eating);
var
slob: set of skill;
begin
slob := [videogames, eating];
end.
我们从slob := [videogames, eating]命令中得到了什么?我猜slob将包含这两种“技能”,但是它是如何由Power来表示
我试图在数组中创建一个对象的随机实例和一个适当排序的实例,但由于某些原因,它不能正常工作。这是它的代码:
import flash.sampler.NewObjectSample;
import flash.display.Sprite;
import flash.events.MouseEvent;
var eating_breakfast:Sprite;
var walking:Sprite;
var swimming:Sprite;
var art:Sprite;
var choices:Array = new Array ();
var i: Number = 0;
eating_