parameter 1 to be mysqli_result, array given in C:\xampp\htdocs\docs\scheme\master\index.php on line 412 $QR = "SELECT bname, bsku FROM brands WHERE id='$delz'";
$rr= mysqli_query($db,$QR) or die ("SQL Err
所以我有一个有趣的问题。我有两个userId和contractId数组要进行比较,看看是否有匹配的结果。然后只显示不匹配的那些。任何帮助都将不胜感激。name, cTitle FROM contracts, users WHERE users.roleId = contracts.roleId ORDER BY users.userId ASC ";$a = mysql_fetch_assoc($rR);