在阅读了ostream::operator << c++参考之后，ostream& operator<< (bool val);ostream& operator<< (unsigned short val);ostream& operat
浏览 0提问于2013-04-15得票数 10
:110:7: note: std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits, _Traits>::__ostream_type = std::basic_ostream<char>]
/usr/include/c++/4.6/ostream:110:7: note:
浏览 9提问于2014-03-23得票数 26
回答已采纳
7回答
4.9/ostream:117:7: note: std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT/usr/include/c++/4.9/ostream:127:7: note: std::basic_ostream<_CharT, _Traits>::__ostream</
浏览 11提问于2014-08-04得票数 54
回答已采纳
& operator<<(ostream &, A &);
out<<a.val;
return/include/c++/4.5.0/ostream:108:7: note: candidates are: std::basic_ostream<_CharT, _Tra
浏览 2提问于2010-05-28得票数 1
回答已采纳
:108:7: note: candidates are: std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(std::basic_ostream<_CharT, _Traits>::__ostream_type& (*)(std::basic_ostream<_Cha
浏览 5提问于2011-12-13得票数 4
回答已采纳
:__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(std::basic_ostream<_CharT, _Traits>::__ostream_type& (*)(std::basic_ostream<_CharT, _Traits>::__ostream_type&)) [with _CharT = char; _Traits>
浏览 62提问于2021-02-12得票数 1
2回答
/include/c++/4.6.0/ostream:110:7: note: std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream/include/c++/4.6.0/ostream:119:7: note: std::basic_ostream<_CharT, _Traits>::__
浏览 3提问于2011-09-19得票数 0
2回答
:106:7: note: std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(std::basic_ostream<_CharT, _Traits>::__ostream_type& (*)(std::basic_ostream<_CharT, _Traits, _Tr
浏览 0提问于2012-07-03得票数 1
回答已采纳
to `html_ostream_end_span(any_ostream_representation*, char const*)'../term-styled-ostream.oo.c:91: undefined reference to `term_ostream_set_weight(any_ostream_represent
浏览 2提问于2013-12-18得票数 1
回答已采纳
(OStream &, const T &);
void print(OStream &,
template<typename OStream<
浏览 0提问于2018-10-30得票数 3
回答已采纳
:108:7: note: candidate: 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(std::basic_ostream<_CharT, _Traits>::__ostream_type& (*)(std::basic_ostream<_Ch
浏览 1提问于2022-01-20得票数 0
回答已采纳
/include/c++/4.4.6/ostream:108: note: candidates are: std::basic_ostream<_CharT, _Traits>& std::basic_ostream/include/c++/4.4.6/ostream:117: note: std::basic_ostream<_CharT, _Traits>&
浏览 2提问于2013-06-27得票数 0
回答已采纳
2回答
例如，如果我想通过转换为函数，如func(std::ostream::operator << (int))typedef ostream& (*out)(int);
out o = std::ostreamostream&
浏览 1提问于2013-08-02得票数 3
1回答
: std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(std::basic_ostream<_CharT, _Traits>::__ostream_type& (*)(std::basic_ostream<_CharT, _Traits>::__ostre
浏览 0提问于2019-11-25得票数 1
回答已采纳
:108:7: note: std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(std::basic_ostream<_CharT, _Traits>::__ostream_type& (*)(std::basic_ostream<_CharT, _Traits, _Tr
浏览 4提问于2016-10-19得票数 0
我在试图继承std::ostream和使用自定义operator <<时遇到了一些困难，这基本上是在做一些工作，然后转发到std::ostream <<，例如：struct ostream : std::ostream{ template<typename因为由于不完
浏览 0提问于2019-03-30得票数 2
回答已采纳
& operator<< (short val); std::ostream& operator<< (int val); std::ostream& operator<< (lo
浏览 8提问于2015-03-28得票数 2
回答已采纳
2回答
void NumberGeneration<N>::out(std::ostream&) [with int N = 1000; std::ostream = std::basic_ostream<charvoid NumberGeneration<N>::out(std::ostream&) [with int N = 1000; std::ostream = std::basic_ostream<char, _Traits>:
浏览 10提问于2014-08-27得票数 2
回答已采纳
2回答
我阅读了很多主题，看起来我做得还不错，但当我尝试编译以下代码时，再次出现上述错误：#include <ostream>{ ostream m_oStream;
CLogger(ostream& oStream);
浏览 0提问于2012-12-19得票数 2
回答已采纳
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