Python通过检查是否存在冲突来解决哈希冲突。为什么'a in s‘不检查相等,而'b in s’检查?在散列()和eq()之间是否调用id()?.: def __eq__(self, other): ...: return False ...: print "not equality"
...: return not s
我实现了一个类和它的元类,这两个类都定义了包括__eq__和__hash__在内的二进制dunder方法。元类的__eq__方法应该简单地实例化该类,然后将比较结果传递给类运算符。= other
return 0 #would be implemented accordingly with a correct hastype/test.py", line 14, in __eq__
if isinstance(ot