Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
push(x) – Push element x onto stack. pop() – Removes the element on top of the stack. top() – Get the top element. getMin() – Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --> Returns -3.
minStack.pop();
minStack.top(); --> Returns 0.
minStack.getMin(); --> Returns -2.
主要是模拟写一个最小栈。要注意push时可能会输入null。需要使用双栈实现,一个保存数据,一个保存最小值。由于随着数据出栈,最小值是不断变化的,因此需要一个最小值栈来保存最小值。
class MinStack {
private Stack<Integer> stack = new Stack<>();
private Stack<Integer> minStack = new Stack<>();
public void push(int x) {
if(minStack.isEmpty() || x <= minStack.peek()) {
minStack.push(x);
}
stack.push(x);
}
public void pop() {
if(stack.peek().equals(minStack.peek())) {
minStack.pop();
}
stack.pop();
}
public int top() {
return stack.peek();
}
public int getMin() {
return minStack.peek();
}
}
扫码关注腾讯云开发者
领取腾讯云代金券
Copyright © 2013 - 2025 Tencent Cloud. All Rights Reserved. 腾讯云 版权所有
深圳市腾讯计算机系统有限公司 ICP备案/许可证号:粤B2-20090059 深公网安备号 44030502008569
腾讯云计算(北京)有限责任公司 京ICP证150476号 | 京ICP备11018762号 | 京公网安备号11010802020287
Copyright © 2013 - 2025 Tencent Cloud.
All Rights Reserved. 腾讯云 版权所有