– 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
SELECT t1.* FROM
(SELECT st.*,c.c_id,c.c_name,sc.s_score FROM student st
LEFT JOIN score sc ON sc.s_id=st.s_id
INNER JOIN course c ON c.c_id =sc.c_id AND c.c_id="01"
ORDER BY sc.s_score DESC LIMIT 1,2) t1
UNION ALL
SELECT t2.* FROM
(SELECT st.*,c.c_id,c.c_name,sc.s_score FROM student st
LEFT JOIN score sc ON sc.s_id=st.s_id
INNER JOIN course c ON c.c_id =sc.c_id AND c.c_id="02"
ORDER BY sc.s_score DESC LIMIT 1,2) t2
UNION ALL
SELECT t3.* FROM
(SELECT st.*,c.c_id,c.c_name,sc.s_score FROM student st
LEFT JOIN score sc ON sc.s_id=st.s_id
INNER JOIN course c ON c.c_id =sc.c_id AND c.c_id="03"
ORDER BY sc.s_score DESC LIMIT 1,2) t3
这是一道mysql难题,也是经典题,搞懂这题就懂得一类题了.
逐条解析 1.从学生表当中选择
SELECT t1.* FROM (student)
2.将学生表和分数表连接从中选择学生信息,课程id,课程名字,分数
SELECT st.*,c.c_id,c.c_name,sc.s_score FROM student st
LEFT JOIN score sc ON sc.s_id=st.s_id
3.将学生表和课程表连接,倒序 ,抽取第2,第3名 ,且课程id为 01的课程信息 并按分数归类
INNER JOIN course c ON c.c_id =sc.c_id AND c.c_id="01"
ORDER BY sc.s_score DESC LIMIT 1,2
猜你喜欢: – 25、查询各科成绩前三名的记录
– 42、查询每门功成绩最好的前两名
扫码关注腾讯云开发者
领取腾讯云代金券
Copyright © 2013 - 2025 Tencent Cloud. All Rights Reserved. 腾讯云 版权所有
深圳市腾讯计算机系统有限公司 ICP备案/许可证号:粤B2-20090059 深公网安备号 44030502008569
腾讯云计算(北京)有限责任公司 京ICP证150476号 | 京ICP备11018762号 | 京公网安备号11010802020287
Copyright © 2013 - 2025 Tencent Cloud.
All Rights Reserved. 腾讯云 版权所有