我有一个数据帧(df),其中我希望将每一列与最后一列进行匹配,以便为每一列提供新值。
以下是我的示例数据帧(df):
> df
S1 S2 S3 S4 S5 main
Gene1 1 1 1 1 2 1
Gene2 1 2 1 1 1 1
Gene3 1 1 1 1 2 2
Gene4 2 1 1 1 1 1
Gene5 1 2 1 2 1 1
Gene6 1 1 1 1 1 2
Gene7 NA NA 2 1 1 1
Gene8 1 2 1 1 1 2
Gene9 2 1 1 2 1 1
我希望将我的1到5列中的每一列与满足以下条件的最后一列进行匹配。下面的“%s”表示从1到5的每一列。
If S = 2 and main = 2, then value is True Positive (TP)
If S = 2 and main = 1, then value is False Positive (FP)
If S = 1 and main = 2, then value is False Negative (FN)
If S = 1 and main = 1, then value is True Negative (TN)
And NAs to remain as NAs.
因此,我的新数据框(df_updated)应该如下所示。
> df_updated
S1 S2 S3 S4 S5
Gene1 TN TN TN TN FP
Gene2 TN FP TN TN TN
Gene3 FN FN FN FN TP
Gene4 FP TN TN TN TN
Gene5 TN FP TN FP TN
Gene6 FN FN FN FN FN
Gene7 NA NA FP TN TN
Gene8 FN TP FN FN FN
Gene9 FP TN TN FP TN
我知道match函数,但我不确定如何循环它们,并对每一列使用上述特定的匹配。
感谢您的帮助,谢谢。
发布于 2019-07-03 12:18:10
你可以使用dplyr的case_when
library(dplyr)
mutate_all(df, ~case_when(
.x < main ~ "FN",
.x > main ~ "FP",
near(.x, 1) & near(.x, main) ~ "TN",
near(.x, 2) & near(.x, main) ~ "TP"
)) %>%
select(-main)
#> S1 S2 S3 S4 S5
#> 1 TN TN TN TN FP
#> 2 TN FP TN TN TN
#> 3 FN FN FN FN TP
#> 4 FP TN TN TN TN
#> 5 TN FP TN FP TN
#> 6 FN FN FN FN FN
#> 7 <NA> <NA> FP TN TN
#> 8 FN TP FN FN FN
#> 9 FP TN TN FP TN
发布于 2019-07-03 12:28:00
使用base R,您还可以创建一个嵌套了ifelse
的函数,并将该函数应用于每一列并获取值。
get_value <- function(x,main) {
ifelse(main == 2 & x == 2, "TP",
ifelse(main == 1 & x == 2, "FP",
ifelse(main == 2 & x == 1, "FN",
ifelse(main == 1 & x == 1 ,"TN", NA))))
}
df1 <- df[-ncol(df)]
df1[] <- lapply(df1, get_value, df$main)
df1
# S1 S2 S3 S4 S5
#Gene1 TN TN TN TN FP
#Gene2 TN FP TN TN TN
#Gene3 FN FN FN FN TP
#Gene4 FP TN TN TN TN
#Gene5 TN FP TN FP TN
#Gene6 FN FN FN FN FN
#Gene7 <NA> <NA> FP TN TN
#Gene8 FN TP FN FN FN
#Gene9 FP TN TN FP TN
https://stackoverflow.com/questions/56869869
复制