问如何同时刷新HTTPServeletResponse中的两个文件

EN

String absolutePath = context.getRealPath("resources/ZipFolders");
String inputFile = Paths.get(absolutePath + "/Attachments.zip").toAbsolutePath().toString();
File finalFile = new File(inputFile);
ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream(finalFile));

String absolutePath2 = context.getRealPath("resources/Spreadsheets");
String inputFile2 = Paths.get(absolutePath2 + "/Validation_Spreadsheet.xlsx").toAbsolutePath().toString();
File file = new File(inputFile2);
byte[] bytes = IOUtils.toByteArray(new FileInputStream(file));
ZipEntry zipEntry = new ZipEntry("Validation_Spreadsheet.xlsx");
zipOut.putNextEntry(zipEntry);
zipOut.write(bytes);
zipOut.closeEntry();
zipOut.close();
response.setContentType("application/zip");
response.setHeader("Content-disposition", "attachment;filename=attachment_trial.zip");
response.getOutputStream().write(IOUtils.toByteArray(new FileInputStream(finalFile)));
System.err.println("above flush>>>>>>>>>>>>>>");
response.getOutputStream().flush();

responsetrial.setContentType("application/vnd.openxmlformats-officedocument.spreadsheetml.sheet");
responsetrial.setHeader("Content-disposition", "attachment; filename=TransactionErrors.xlsx");
responsetrial.getOutputStream().write(IOUtils.toByteArray(new FileInputStream(file)));
System.err.println("above flush2>>>>>>>>>>>>>>");
responsetrial.getOutputStream().flush();