问将参数从cmd传递到python脚本

EN

import argparse

# Define the parser
parser = argparse.ArgumentParser(description='Short sample app')

# Declare an argument (`--algo`), saying that the 
# corresponding value should be stored in the `algo` 
# field, and using a default value if the argument 
# isn't given
parser.add_argument('--algo', action="store", dest='algo', default=0)

# Now, parse the command line arguments and store the 
# values in the `args` variable
args = parser.parse_args()

# Individual arguments can be accessed as attributes...
print args.algo

python "C:\Users\test.pyw" "arg1" "arg2"

print ("This is the name of the script= ", sys.argv[0])
print("Number of arguments= ", len(sys.argv))
print("all args= ", str(sys.argv))
print("arg1= ", sys.argv[1])
print("arg2= ", sys.argv[2])

import sys, getopt


def main(argv):

    # default algorithm:
    algorithm = 1

    # parse command line options:
    try:
       opts, args = getopt.getopt(argv,"a:",["algorithm="])
    except getopt.GetoptError:
       <print usage>
       sys.exit(2)

    for opt, arg in opts:
       if opt in ("-a", "--algorithm"):
          # use alternative algorithm:
          algorithm = arg

    print "Using algorithm: ", algorithm

    # Positional command line arguments (i.e. non optional ones) are
    # still available via 'args':
    print "Positional args: ", args

if __name__ == "__main__":
   main(sys.argv[1:])

python <scriptname> -a2               # use algorithm 2
python <scriptname> --algorithm=2    # ditto