问如何计算OCR系统的置信度分数？

EN

#include <iostream>
#include <vector>
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>

using namespace std;

double getWeightedConfidence(vector<pair<char /* character */, double /*confidence of that character */>> word) {
    if (word.empty()) {
        return 1.0;
    }
    
    double confidence = 0;
    
    if (isdigit(word[0].first)) {
        // okay it is a number
        
        double weight = 1;
        double sumOfWeights = 0;
        for (const auto &c : word) {
            confidence += c.second * weight;
            sumOfWeights += weight;
            weight /= 10; // you can decay it by whatever number you want based on how much do you think next digit is less valueble then previous
        }
        
        confidence /= sumOfWeights;
    } else {
        // not a number - just calculate a normal average
        for (const auto &c : word) {
            confidence += c.second;
        }
        
        confidence /= word.size();
    }
    
    return confidence;
}

int main() {
    
    vector<pair<char, double>> number_with_first_digit_wrong;
    number_with_first_digit_wrong.emplace_back('7', 0.1);
    number_with_first_digit_wrong.emplace_back('4', 0.9);
    number_with_first_digit_wrong.emplace_back('6', 0.9);
    number_with_first_digit_wrong.emplace_back('2', 0.9);
    number_with_first_digit_wrong.emplace_back('.', 0.9);
    number_with_first_digit_wrong.emplace_back('9', 0.9);
    
    vector<pair<char, double>> number_with_last_digit_wrong;
    number_with_last_digit_wrong.emplace_back('7', 0.9);
    number_with_last_digit_wrong.emplace_back('4', 0.9);
    number_with_last_digit_wrong.emplace_back('6', 0.9);
    number_with_last_digit_wrong.emplace_back('2', 0.9);
    number_with_last_digit_wrong.emplace_back('.', 0.9);
    number_with_last_digit_wrong.emplace_back('9', 0.1);
    
    
    cout << getWeightedConfidence(number_with_first_digit_wrong) << " " << getWeightedConfidence(number_with_last_digit_wrong) << endl;
    
    return 0;
}